(x^2)+(6*x)+9=x+3
(x^2)+(5*x)+6=0
d=25-(4*6)=1
x[1]=((-5)+1)/2=-3
x[2]=((-5)-1)/2=-2

ha! i`m genius^^

or, you could, you know, factor it

x^2 + 6x + 9 = x + 3
x^2 + 5x + 6 = 0
(x + 2)(x + 3) = 0
x = -2 or x = -3

Factoring feels like cheating at times...

x = (-b ± √(b2 -4ac))/(2ab)

comment #32121
Don't use him for reference, kids; that's wrong.

2a, not 2ab, and its b^2

x = (−b ± √(b² − 4ac))∕(2a)

Easier:
x^2+6x+9=x+3
(x+3)^2=x+3
x+3=1
x=-2

comment #33652
Except you lost an answer.

Anonymous said:
Easier:
x^2+6x+9=x+3
(x+3)^2=x+3
x+3=1
x=-2

you divided by zero.